3[3-(2-2x)]+2x=2(4x+4)-5

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Solution for 3[3-(2-2x)]+2x=2(4x+4)-5 equation: 


Simplifying
3[3 + -1(2 + -2x)] + 2x = 2(4x + 4) + -5
3[3 + (2 * -1 + -2x * -1)] + 2x = 2(4x + 4) + -5
3[3 + (-2 + 2x)] + 2x = 2(4x + 4) + -5

Combine like terms: 3 + -2 = 1
3[1 + 2x] + 2x = 2(4x + 4) + -5
[1 * 3 + 2x * 3] + 2x = 2(4x + 4) + -5
[3 + 6x] + 2x = 2(4x + 4) + -5

Combine like terms: 6x + 2x = 8x
3 + 8x = 2(4x + 4) + -5

Reorder the terms:
3 + 8x = 2(4 + 4x) + -5
3 + 8x = (4 * 2 + 4x * 2) + -5
3 + 8x = (8 + 8x) + -5

Reorder the terms:
3 + 8x = 8 + -5 + 8x

Combine like terms: 8 + -5 = 3
3 + 8x = 3 + 8x

Add '-3' to each side of the equation.
3 + -3 + 8x = 3 + -3 + 8x

Combine like terms: 3 + -3 = 0
0 + 8x = 3 + -3 + 8x
8x = 3 + -3 + 8x

Combine like terms: 3 + -3 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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